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Is it true that for a value of n (n-principal quantum number), the value of m_l (m_l-magnetic quantum number) is equal to n^2? If it is true, can you please explain this
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Quantum Numbers Schrödinger's equation requires 3 quantum numbers (although there are a total of 4 quantum numbers) - ppt video online download
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Chemistry - Electron Structures in Atoms (31.5 of 40) Orbital [Magnetic Quantum Number] m(l) - YouTube
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